A rectangular loop of wire,supporting a mass | vedclass

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(C) The magnetic force on a current-carrying wire is given by $\vec F = I(\vec L 	imes \vec B)$.In the rectangular loop,the current flows clockwise.

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The weight rises due to a vertical force caused by the magnetic field.

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(C) The magnetic force on a current-carrying wire is given by $\vec F = I(\vec L 	imes \vec B)$.In the rectangular loop,the current flows clockwise. The top segment $PQ$ of length $a$ is inside the magnetic field $\vec B$ (pointing into the page).Using the right-hand rule,the force on segment $PQ$ is directed upwards.The magnitude of this magnetic force is $F_m = i a B$.The downward force due to gravity is $F_g = mg$.The net force on the loop is $F_{net} = F_m - F_g = i a B - mg$.Given that $i > mg/Ba$,it follows that $i a B > mg$,which means $F_{net} > 0$.Since the net force is positive (upwards),the weight rises due to the vertical magnetic force.

$A$ rectangular loop of wire,supporting a mass $m$,hangs with one end in a uniform magnetic field $\vec B$ pointing into the plane of the paper. $A$ clockwise current $i$ is set up such that $i > mg/Ba$,where $a$ is the width of the loop. Then:

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